Question

A pole 6m pass a shadow 2root3 long on the ground. Find the angle of elevation?

Answer 1

Height of pole, h = 6 cm
shadow= Base, b = 2√3 cm
 Let the elevation be θ
Then, tanθ = 6/(2√3) = √3
tanθ = √3
⇒θ = 60°

Answer 2

Answer:

Step-by-step explanation:

Given :-

Height of the pole = 6 m

length of shadow = 2√3 m

To find :-

The angle of elevation of sun

Solution :-

Let θ be angle of elevation.

ø is angle of elevation

⇒ Tan ø = height/shadow length

⇒ Tan ø = 6/2√3

⇒ Tan ø = √3

⇒ ø = π/3

Angle of elevation is 60°