Question

A pole 81 m high broke at a point but did not separate. Its top touched the ground 27 m from its base. At what
height above the ground did the pole break?
solve this fast...​

Answer 1

PROCEDURE :

(81-x)² = (27)²+x²

=> x² = (81-x)² - (27)² = (81-x+27) (81-x-27) = (108-x) (54-x) = 5832-108x-54x+x² = 5832-162x+x²

So, x² = 5832-162x+x²

=> 162x = 5832+x²-x² = 5832+(x²-x²) = 5832+0 = 5832

Again, 162x = 5832

=> x = 5832/162 = 36

Hence, we can now say that, the pole broke at a height of 36 metres above the ground.

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