A pole 81m high broke at a point but did not separate. Its top touched the ground 27m from its base .At what height above the ground did the pole break?
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Suppose the point from which the pole broke is x meters above the ground. then the length of AC will be (81 - x)m.
ABC is right angled triangle by applying Pythagoras theorem.
AC2 = AB2 + BC2
= (81 - x)2 = x2 + 27 2
= 6561+ x2 - 162x = x2 + 729
= 5832 = 162x
= x = 36
Height from which the pole broke is 36 meters above the ground.
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