Question

A pole 81m high broke at a point but did not seperate.its top touched the ground 27m from its base.At what height above the ground did the pole break?VERY IMPORTANT PLZ GIVE ANSWER FASTLY​

Answer 1

Answer--

Hey there,

Suppose the point from which the pole broke is x meters above the ground. then the length of AC will be (81 - x)m.

ABC is right angled triangle by applying Pythagoras theorem.

AC2 = AB2 + BC2

= (81 - x)2 = x2 + 27 2

= 6561 + x2 - 162x = x2 + 729

= 5832 = 162x

= x = 36

Height from which the pole broke is 36 meters above the ground.

Hope this helps!

Answer 2

Answer:

simple the hypotonese we find it the high is 81m and the base is 27m the find the hyptonease. we easily find it the sum of the number in square.

Step-by-step explanation:

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