A pole 81m high broken at a point but did not separate. Its top touched the ground 27m from its base. At what height above the ground did the pole bteak
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let take the pole broken from height x m then the length of broken part will be 81-x.
then broken part will be hypotenuse
therefore AC^2=AB^2+BC^2
(81-x)^2=x^2+27^2
6561+x^2-162x=729+x^2
6561-729=162x
x=36
therefore 36m is a answer.
i hope these will helpful
then broken part will be hypotenuse
therefore AC^2=AB^2+BC^2
(81-x)^2=x^2+27^2
6561+x^2-162x=729+x^2
6561-729=162x
x=36
therefore 36m is a answer.
i hope these will helpful
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