Math, asked by dharshankiru333, 2 days ago

A pole 8m high is fixed on the top of the tower the angle of elevation of top of as the pole as observed from a point A on the ground is alpha such that sin alpha = 4/5 and the angle of depression of point A from the top of tower is 45°what is the height of the tower​

Answers

Answered by Anonymous
8

Answer:

A pole 8m high is fixed on the top of the tower the angle of elevation of top of as the pole as observed from a point A on the ground is alpha such that sin alpha = 4/5 and the angle of depression of point A from the top of tower is 45°what is the height of the tower

Answered by swethassynergy
0

The height of tower is 24 meter.

Step-by-step explanation:

Given:

8 meter high a pole is fixed on the top of the tower.

the angle of elevation on top of the pole as observed from a point A on the ground is an alpha and sin \alpha  = 4/5.

The angle of depression of point A from the top of the tower is 45\textdegree.

To Find:

The height of tower.

Formula Used:

tan\theta = \frac{perpendicular}{base}  

Identity  sin^{2}x+cos^{2} x=1

Solution:

Let the height of the tower is P.

Let the distance between the tower and point A is Q.

As given -the height of the pole is 8m.

 As given - the Angle of depression from the top of tower to point A is 45\textdegree.

Then,  tan 45\textdegree = \frac{P}{Q}

                  1=\frac{P}{Q}

                  Q=P   -------------- equation no.01

As given - the angle of elevation on top of the pole as observed from a point A on the ground is an alpha and sin \alpha = 4/5.

sin\alpha =\frac{4}{5} \\

Using identity sin^{2}\alpha +cos^{2} \alpha =1

cos^{2} \alpha =1-sin^{2}\alpha

cos\alpha  =\sqrt{ 1-sin^{2}\alpha }

cos\alpha  =\sqrt{ 1-(\frac{4}{5} )^{2} }    

cos\alpha  =\sqrt{ 1-(\frac{16}{25} ) }

cos\alpha  =\sqrt{ (\frac{25-16}{25} ) }  

cos\alpha  =\sqrt{ (\frac{9}{25} ) } =\frac{3}{5}

tan\alpha =\frac{sin\alpha }{cos\alpha }  = \frac{\frac{4}{5} }{\frac{3}{5} }

tan\alpha =\frac{4}{3}

Then,  \frac{4}{3}  =\frac{8+P}{Q}

Putting the value of Q from equation no.01.

\frac{4}{3}  =\frac{8+P}{P}

4P= 24+ 3P

P=24

Thus, the height of tower is 24 meter.

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