Question

A pole brock at a point but did not separate its top touches the ground at a distance of 5 M from its base if the point where it Brock is at a height of 12 m from the ground what were the total height of the pole before it broke

Answer 1

let the point where it broke be B.

the base be C.

the fallen top be A.

ABC form right triangle where angle c is 90.

AC is 5m.

BC is 12 m.

by pythagoras theorem,

AB2 = BC2 + AC2

AB2 = 12square + 5square

AB2 = 144 + 25

AB2 = 169

Ab = 13

total height of pole before breaking = 12m + 13m

=25m

Answer 2

pole broke at 12m and distance is 5m so, it will form a right angle triangle
height will be 12m
base will be 5m
hypotenuse will be length of pole above the point from where the pole is broke

H ^2 = P^2 + B ^2
H^2 = 12 ^2 + 5 ^2
H^2 = 144 + 25
H ^2 = 169
H = √169
H = 13

Length of total pole will be,
12 + 13
25m