a pole broke at a point but did not separate. its top touched the ground at a distance of five meter its base. if the point where it broke is at a height of 12m from the ground, what was the total height of the pole before it broke
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Hi,
Here's ur answer:-
As the top point of of pole touches the ground, the structure would look like a right angled triangle. the straight part of pole is here the perpendicular, the distance between the top point and the bottom point of pole is the base and the bent part of pole is the hypotenuse.
To find the actual length of the pole, we have to find the sum of the perpendicular and the hypotenuse.
Firstly, let's find the hypotenuse ( that is unknown here)
H² = P² + B²
⇒H = √(P²+B²) = √(12²+5²) = √(144+25) =√169 = 13 m
So, the Hypotenuse is 13 m
Length of the pole = 13 m + 12 m = 25 m
HOPE IT HELPS (^_^)
Here's ur answer:-
As the top point of of pole touches the ground, the structure would look like a right angled triangle. the straight part of pole is here the perpendicular, the distance between the top point and the bottom point of pole is the base and the bent part of pole is the hypotenuse.
To find the actual length of the pole, we have to find the sum of the perpendicular and the hypotenuse.
Firstly, let's find the hypotenuse ( that is unknown here)
H² = P² + B²
⇒H = √(P²+B²) = √(12²+5²) = √(144+25) =√169 = 13 m
So, the Hypotenuse is 13 m
Length of the pole = 13 m + 12 m = 25 m
HOPE IT HELPS (^_^)
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