A pole broke at a point but did not separate, its top touched the ground at a distance of 7m from it’s
base. If the point where it broke is at a height of 24m from ground. What was the total height of the
pole before it broke?
Answers
Distance between the pole and the
ground = 7m
Distance between the ground and the point at
the pole where it broke= 24m
Let the distance between the point at which the
pole broke and the point where it touched the
ground be "X"
By, Pythagoras Theorem:
X^2 = 7^2 + 24^2
X^2 = 49 + 576
X^2 = 625
X = √625
X = 25
Therefore, the height of the pole
= (X + 24)m
= (25+24)m
= 49m
Hope you found it helpful!
Answer:
The total height of the pole is 49m
Step-by-step explanation:
- let AB be the height of remaining part of the broken pole = 24 m
- BC be the distance from the base of the pole to the point where the top of the pole touches the ground = 7m
- AC be the broken part of the pole
ACB forms a triangle ️
By phythagorus theorem
AC² = AB² + BC²
= (24)² + (7)²
= 576 + 49
AC² = 625
(squaring on both sides)
AC = 25
Therefore the total height of the pole
= AC + AB
= 24+25
= 49 m