Question

a pole cast a shadow of length 2√3 m on the ground when the sun elevation is 60° . find the height of the pole. ​

Answer 1

Answer:

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Step-by-step explanation:

The height of the pole is. Let the height of the pole be h metres. Then, h2√3=tan60∘=√3. ⇒h=(2√3×√3)=6.

Answer 2

Step-by-step explanation:

Refer the attachment.

Let AB be the pole.

⇒ tan60° = √3

⇒ Perpendicular/Base = √3

⇒ AB/2√3 = √3

⇒ AB = √3 * 2√3

⇒ AB = 2 * 3

⇒ AB = 6 m

The pole's height is 6 m.