a pole casts a shadow length 2 route 3 m on the ground , when the Sun's elevation is 60 degree find the height of the pole
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Let triangle ABC be a right triangle right angled at B and AB be the base of it.
Assume BC to be the height of the pole and let it be x m.
Now AB will be the shadow.
and angle A will be 60
so tan 60 = perpendicular / base
tan 60= BC/ AB
root 3= x/ 2root3
root 3 × 2 root3= x
2× 3= x
6 = x
height of pole = 6m.
Assume BC to be the height of the pole and let it be x m.
Now AB will be the shadow.
and angle A will be 60
so tan 60 = perpendicular / base
tan 60= BC/ AB
root 3= x/ 2root3
root 3 × 2 root3= x
2× 3= x
6 = x
height of pole = 6m.
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