Question

A pole casts a shadow of length 2 3 m on the ground,

when the Sun’s elevation is 60º. Find the height of the

pole.​

Answer 1

Let the height of the pole be h metres. Then,

h2√3=tan60∘

=√3.

⇒h=(2√3×√3)=6.

Answer 2

Let AB be the pole and BC be its shadow. We have

$bc = 2 \sqrt{3m } \: and \: acb = 60degree$

$in \ \: triangle \: abc$

$tan \: 60 \: degree = \frac{ab}{bc}$

$= \sqrt{3} = \frac{ab}{2 \sqrt{3} }$

therefore

$ab = 6m$