A pole casts a shadow of length 2 root 3 metre away on the ground when the sun's elevation is 60 degree. Then find the height of the pole
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1
Answer:
6 m
Explanation:
let the height be x
x/2root3= tan 60
root3 = x/2root3
2root3*root3=x
x = 6m
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4
Answer:
A pole casts a shadow of length 2 root 3 metre away on the ground when the sun's elevation is 60 degree. The height of the pole is 6 meters.
Explanation:
Given the length of the shadow and the angle of elevation of the sun, we can use Trigonometric ratios to find the height of the pole.
In this case we will use Tan
Tan = Opposite side / Adjacent
The length of the shadow is the adjacent side whereas the height of the pole is the opposite.
Now, we have:
Tan 60 = h/2√3
h = Tan 60 × 2√3
Tan 60 = √3
Therefore, we have:
h = √3 × 2√3
h = 6 meters
The height of the pole is 6 meters.
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