A pole casts a shadow of lgth 2√3m on the ground , when the suns elevation is 60°.find the hght of the pole?
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height of pole = 6 m
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We know,
shadow = BC = 2√3 m
pole = AB
In the triangle ABC ,
tan 60° = AB / BC
√3 = AB / 2√3
AB = √3 * 2√3
AB = 2 *3
AB = 6 m
Therefore, the height of the pole is equal to 6 m
shadow = BC = 2√3 m
pole = AB
In the triangle ABC ,
tan 60° = AB / BC
√3 = AB / 2√3
AB = √3 * 2√3
AB = 2 *3
AB = 6 m
Therefore, the height of the pole is equal to 6 m
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