Question

A pole is 2√3 m high. It shadows length is
2m. Then what will be the angle of elevation
of light source.​

Answer 1

Step-by-step explanation:

tan theta=2√3/2=√3

tan 60°=√3

so theta=60°

Answer 2

$\boxed{\huge{\bf{Answer=60°}}}$

Step by Step Explanation

Let the angle of elevation = ∅(theta)

and the pole = AB(as shown in fiqure.

A triangle ∆ABC is formed in which we have to find angle C.

By trigonometric angle values

tan∅=perpendicular/base______eq'n(1)

here,

for angle C

perpendicular=2√3m and

base = 2m

putting values in equation (1)

tan∅=(2√3)/2

tan∅=√3____________eq'n(2)

By trigonometric angle values

tan60°=√3___________eq'n(3)

by comparing equation (2) and (3)

∅=60°