A pole is painted as 1/10th red, 1/20th white, 1/30th blue, 1/40th black, 1/50th violet, 1/60th yellow and the rest green. If you portion in green has length 12.08 metre, length of the pole is
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1-add all fractions. the ans remain 453/600 . then remain fraction multiplied with 12.08 . the ans 16 meter
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Solution:-
Let the length of the pole be 'x' meter.
Therefore, according to the question.
Total length of the all parts (except in green colour) = x/10 + x/20 + x/30 + x/40 + x/50 + x/60
Taking L.C.M and then solving it, we get.
(60x + 30x + 20x + 15x + 12 x + 10x)/600
= 147x/600
147x/600 is the length of the parts of the pole which are painted in red, white, blue, black, violet and yellow respectively.
Now remaining part is in green colour.
⇒ x - 147x/600 = 12.08
Taking L.C.M. and solving it.
⇒ (600x - 147x)/600 = 12.08
⇒ 453x/600 = 12.08
⇒ 453x = 7248
⇒ x = 7248/453
⇒ x = 16
So, the total length of the pole is 16 meter.
Answer.
Let the length of the pole be 'x' meter.
Therefore, according to the question.
Total length of the all parts (except in green colour) = x/10 + x/20 + x/30 + x/40 + x/50 + x/60
Taking L.C.M and then solving it, we get.
(60x + 30x + 20x + 15x + 12 x + 10x)/600
= 147x/600
147x/600 is the length of the parts of the pole which are painted in red, white, blue, black, violet and yellow respectively.
Now remaining part is in green colour.
⇒ x - 147x/600 = 12.08
Taking L.C.M. and solving it.
⇒ (600x - 147x)/600 = 12.08
⇒ 453x/600 = 12.08
⇒ 453x = 7248
⇒ x = 7248/453
⇒ x = 16
So, the total length of the pole is 16 meter.
Answer.
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