A pole is standing vertically in water in such a way that its height under water is √3 m and above water
surface is √5 m. When the angle of elevation of the sun was θ = cosିଵ(2/3), then the length of the shadow
was ‘κ’ m. What is the numerical value of κ ?
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Let the height of the tower be h
∴height of the shadow=
3
h
In a △ABC,
tan∠ACB=
3h
⇒tan∠ACB= 31
∴∠ACB=60 ∘
Therefore, angle of elevation is 30 ∘
.
Explanation:
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