a pole of height 10 m cast a shadow of 10√3 m long on the ground . find the suns altitude.
TPS:
angle of elevation can be found but altitude?
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Answered by
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Let the sun makes angle Ф with horizon.
Then the height h = 10 m
base b = 10√3 m
We have tanФ= 10/10√3 = 1/√3 = tan 30
Ф= 30 degree
Sun is at 30 degree elevation
Then the height h = 10 m
base b = 10√3 m
We have tanФ= 10/10√3 = 1/√3 = tan 30
Ф= 30 degree
Sun is at 30 degree elevation
Answered by
1
tanФ=10/10√3
=1/√3
tanФ=30
=1/√3
tanФ=30
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