Question

A pole of length 1.00 m stands half dipped in a swimming pool with water level 50.0cm higher than the bed . the refractive index of water is 1.33 and sunlight is coming at an angle of 45° with the vertical .find the length of the shadow of the pole on the bed

Answer 1

hope it helps you..............

Answer 2

Thus the shadow length is 81.2 cm

Step-by-step explanation:

Shadow Length = BA' = BD + A'D = 0.5 + 0.5 tan r

Now 1.33 = Sin 45° / Sin r

Sin r = 0.53

Cos r = √ 1 - sin^2 r = √ 1 - (0.53) = 0.85

So tan r = 0.6235

Now shadow length = (0.5) ( 1 + 0.6235) = 81.2 cm

Thus the shadow length is 81.2 cm