a pole of length 12m casts a shadow of length 15.6 m find length of shadow cast by another pole of length 18 m
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Solution:-
Height of the pole H1, = 10 m
Length of the shadow of the pole, X1 = 2 m
Height of the tower = H2 m
Length of the shadow of the tower, X2 = 60 m
Since, if the two shadows cast, that will form two triangles which will be similar. Therefore, the ratio of their corresponding sides will be equal.
Therefore.
H1/H2 = X1/X2
10/H2 = 2/60
H2 = 600/2
H2 = 300 m
Hence the height of the tower is 300 m. Answer......
I hope it helps you
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