Question

a pole of light is 50m high from which the angle of depression of a ship is 30. find the distance of the ship from the pole? plss give the ans with full explanation

Answer 1

perpendicular = 50m Distance of the ship from pole = Base tan30° = perpendicular / base
$1 \div \sqrt{3} = 50 \div base$

$base = 50 \sqrt{3}$

Answer 2

Given:

A pole of light is 50m high from which the angle of depression of a ship is 30.

To Find:

Find the distance of the ship from the pole

Step-by-step explanation:

• Here this type of Question can be solved by using the concept of Height and Distance .
• In this type of question we solve this by making a triangle and then using the trigonometry to solve the required.
• Here the length of pole is given as $50\ m$ and the angle of depression is given as $30$°. This will form a right angled triangled with the perpendicular as $50\ m$ and the base is the required distance we have to find.
• The angle of the triangle is the angle of depression.
• $tan(30)= 50\div x\\x=50\times \sqrt{3}$

This is the final answer $50\times \sqrt{3}$