A pole projected outwards and upwards from a window at height of 20m high on a wall making an angle of 30 degree with the wall if angle of elevation of base and tope of pole from the ground level
60 degrees, find the length of the pole
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Answer:
23.09m
Step-by-step explanation:
let AB = 20m & length of pole be 'BP'
Tan30° = AB/AQ
1/√3 = 20/AQ => AQ = 20√3
BQ = √[ (20)^2 + (20√3)^2 ]
BQ = √1600 = 40m
from triangle BPQ
Tan30° = BP/BQ
1/√3 = BP/40
BP = 40/√3 = 23.09 m
length of pole = 23.09m
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