Question

A pole vaulter takes a huge leap in order to jump over the bar placed 9 meters above the ground. In his first attempt, he is able to reach only 7.845 metres. In how many attempts will he be able to clear the bar, if in each successive attemp he improves 0.231 metres?

Answer 1

Answer:

Required height = 9

Required height = 9initial jump = 7.845

Required height = 9initial jump = 7.845Required increase in height = 9- 7.845= 1.155

Required height = 9initial jump = 7.845Required increase in height = 9- 7.845= 1.155No. of attempts = 1.155/0.231 = 5

Answer 2

He will able to clear the bar in 5 attempts.

Given - Total height, reachable height and improvement

Find - Number of attempts

Solution - Firstly we will be calculating the difference in height which the pole vaulter needs to achieve.

Difference need to cover = 9 - 7.845

Performing subtraction

Difference = 1.155

Now, we will be calculating the number of attempts required.

Pole vaulter improves 0.231 height in number of attempts = 1

Number of attempts to improve to 1.155 height = (1÷0.231)×1.155

Number of attempts = 1.155÷0.231

Number of attempts = 5

Hence, pole vaulter will be able to clear the bar in 5 attempts.

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