A police car is moving at 29 m/s is behind a speeding car moving faster in the same direction as the police car. The radar gun in the police car emits an 8 × 109 Hz electromagnetic wave. The frequency of the returning car wave is measured to be 318 Hz less than the emitted frequency. Find the speeders speed.
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Answer:
z=(318/2) Hz / (8.0*10^9 Hz) = 2*10^(-8)
z=v/c
v=c*z = 3*10^8 m/s * 2 * 10^(-8) = 6 m/s
speedingcar has velocity 6m/s bigger then police car.
Hence, speeding car has velocity 29+6 = 35 m/s
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