Physics, asked by student48, 1 year ago

A Police Car moving on a Highway at 30 km per hour flies of bullet on a speeding car of thieves at 150 km per hour if the muzzle speed of the bullet is 150 METRE per second calculate the speed by which the bullet strikes the car of the thieves

Answers

Answered by sas12
3
velocity of the police car =25/8 m/s. v of b is 150m/s. relative velocity of bullet with respect to polce van=150+25/3 m/s. velocity of thieves car=150*5/18 m/s. speed with which the bullet hits the thieves car =150+25/3 -150*5/18.
Answered by Anonymous
13

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Speed of the police van,

v(p) = 30 km/h = 8.33 m/s

Muzzle speed of the bullet,

v(b) = 150 m/s

Speed of the thief’s car,

v(t )= 192 km/h = 53.33 m/s

Since the bullet is fired from a moving van, its resultant speed can be obtained as: = 150 + 8.33 = 158.33 m/s

Since both the vehicles are moving in the same direction, the velocity with which the bullet hits the thief’s car can be obtained as: v(bt) = v(b) – v(t)= 158.33 – 53.33 = 105 m/s

I hope, this will help you

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