Question

A police is chasing a thief. The police's velocity is 25m/s and the thief's velocity is 20m/s. The distance between them is 500m. How long will it take for the police to catch the thief?

Answer 1

1000m=1km

the distance is

1000

100

=.1km

let time =x

10x=0.1+8x

2x=0.1

x=0.05

it will take the policeman .05hours to catch the thief

the thief would have run .05×8=.4km=400meters

Answer 2

Question:

• A police is chasing a thief. The police's velocity is 25m/s and the thief's velocity is 20m/s. The distance between them is 500m. How long will it take for the police to catch the thief?

Solution:

velocity of the police =25 m / s

velocity of the thief= 20 m / s

Relative velocity of the police with respect to thief is ,

$\implies{V p - V t = 25 - 20 }$

$\implies{V \: rel \: = 5 \frac{m}{s} }$

time taken by the police to catch the thief

$\implies{time = \frac{distance}{velocity} }$

$\implies{time = \frac{500}{5} }$

$\boxed{time =100 \: sec}$