Question

A police jeep is chasing a culprit going on a moter bike. The motor bike crosses a turn at a
72 km/h. The jeep follows it at a speed of 108 km/h, crossing the turn 10 seconds later the
(keeping constant speed). After crossing the turn, jeep acclerates with constant acceleration 2 m/s
Assuming bike travels at constant speed, after travelling a distance 20∆ m. from the turn
catches the bike. Where ∆ is an integer. Find ∆.
Answer Fast
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Answer 1

Answer:

Speed of motor bike=72 km/hr=72x5/18 =20 m/s

Speed of Jeep=90x5/18=25m/s

Let us assume that Jeep catches the bike at a distance of  X m from the turning.

Time taken to civer  distance X m =Distance/time

=x/20 sec

Since jeep starts 10 sec later , so it takes 10s less time to cover the equal distance

Time taken to cover X m will be =x/20 - 10

But from the jeep's speed it comes to be x/25 s

These two must be equal. Hence

x/20-10=x/25

x-200/20=x/25

x-200/4=x/5

5x-1000=4x

x=1000m=1km

∴Hence the jeep will catch up the bike at a distance of 1km

Step-by-step explanation: