Question

A police jeep is chasing a culprit going on a motorbike.
The motorbike crosses a turning at a speed of 72 km/h.
The jeep follows it at a speed of 90 km/h, crossing the
turning ten seconds later than the bike. Assuming that
they travel at constant speeds, how far from the turning
will the jeep catch up with the bike ?​

Answer 1

Answer:

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Answer 2

Given :-

Velocity of the police jeep = 90 km/h

Velocity of the motorbike = 72 km/h

To Find :-

How far from the turning  will the jeep catch up with the bike.

Solution :-

We know that,

• s = Speed
• v = Velocity
• t = Time

Given that,

Velocity of the police jeep = 90 km/h = 25 m/s

Velocity of the motorbike = 72 km/h = 20 m/s

In 10 seconds, the culprit reaches point B from point A on motorbike.

According to the question,

Distance covered by the culprit, say s = $\sf vt = 20 \times 10 = 200 \ m$

∴ Police jeep is 200 m behind the culprit at t = 10 s

Now, relative velocity between both:

$\sf Time=\dfrac{s}{v}$

Substitute their values,

$\sf Time=\dfrac{200}{5} =40 \ s$

Police jeep will move in 40 sec from A to cover distance s,

$\implies \sf s = vt = 25 \times 40$

$\sf = 1000 m=1 \ km$

Thus, the police jeep will catch up with the bike 1.0 km away from the turning.