Question

A police jeep is chasing a culprit going on a motorbike.The motorbike crosses a turning at a speed of 72km/h.The jeep follows it at a speed of 90km/h,crossing the turning 10seconds later than bike . Assuming that they at constant speeds, how far from the turning will be the jeep catch up with the bike.
ANSWER FAST.....
NO SPAMMING☆☆☆

Answer 1

heya frnd 

v(culprit)= 20 mps
v(police)=25 mps

Let at t=0 the police has reached the turning point. This means culprit has already travelled an extra distance D. 

D=20*10+0
=200m

From now let he be caught after time t and covering distance 's'.so

S=20t

And the distance covered by police in this t time.

S+200=25t

Dividing these 2 equations we get

S÷(S+200) = 4÷5

So s=800m or 0.8km

So it's distance from the turning point will be 800+200=1000m or 1km.

Answer 2

here relative velocity =25-20=5m/s

and in 10 sec culprit travel 20×10=200m

so relative displacement=200m

so S=relative velocity×t -1/2×at^2

200=5×t -1/2×0

t=200/5

t=40sec

and in 40 sec jeep travel 40×25=1000m