Question

A police jeep is chasing a culprit going on a motorbike.The motorbike crosses a turning at a speed of 72km/h.The jeep follows it at a speed of 90km/h,crossing the turning 10seconds later than bike . Assuming that they at constant speeds, how far from the turning will be the jeep catch up with the bike.<br />ANSWER FAST.....<br />NO SPAMMING☆☆☆

Answer 1

heya frnd 
v(culprit)= 20 mpsv(police)=25 mps
Let at t=0 the police has reached the turning point. This means culprit has already travelled an extra distance D. 
D=20*10+0=200m
From now let he be caught after time t and covering distance 's'.so
S=20t
And the distance covered by police in this t time.
S+200=25t
Dividing these 2 equations we get
S÷(S+200) = 4÷5
So s=800m or 0.8km
So it's distance from the turning point will be 800+200=1000m or 1km.

Answer 2

$distence = \frac{s1 \times s2}{s2 - s1} \times time \\ \: \: = \frac{20 \times 25}{?25 - 20} \times 10 \\ 500 \times 2 \\ 1000m = 1km \\ \ \: \\ \: (72 \times \frac{5}{18} = 20m |sec) \\ (90 \times \frac{5}{18 } = 25m |sec)$