Question

A police moving on a highway with a speed of 30km/hr fires a bullet at a thief's car speeding away in the same direction with a speed of 192km/hr if the muzzel speed of the bullet is 150m/s the speed with which the bullet hit the theif's car is?

Answer 1

policeman's car speed = 30*5/18 m/s=8.34 m/s
thief's car speed = 192*5/18=53.34 m/s
bullets speed = 150 m/s

considering the reference plane to be ground

bullets effective speed wrt the policeman is 158.34 m/s

bullets relative speed wrt the thief's car is 158.34-53.34 = 105 m/s

Answer 2

==============ⓢⓦⓘⓖⓨ

$\huge\mathfrak\red{hello...frd\:swigy\:here}$

==============ⓢⓦⓘⓖⓨ

Speed of the police van,

v(p) = 30 km/h = 8.33 m/s

Muzzle speed of the bullet,

v(b) = 150 m/s

Speed of the thief’s car,

v(t )= 192 km/h = 53.33 m/s

Since the bullet is fired from a moving van, its resultant speed can be obtained as: = 150 + 8.33 = 158.33 m/s

Since both the vehicles are moving in the same direction, the velocity with which the bullet hits the thief’s car can be obtained as: v(bt) = v(b) – v(t)= 158.33 – 53.33 = 105 m/s

I hope, this will help you

=======================

$<marquee behaviour-move bigcolour-pink><h1>☺ThankYou✌</h1></marquee>$

·.¸¸.·♩♪♫ ⓢⓦⓘⓖⓨ ♫♪♩·.¸¸.·

___________♦♦⭐♦ ♦___________