Question

A policeman and a thief are equidistant from the jewel box. Upon considering jewel box as
origin, the position of policeman is (0, 5). If the ordinate of the position of thief is zero, then
write the coordinates of the position of thief

Answer 1

The coordinates of the thief are (5,0).

Given,

The jewel box is at the origin. The policeman is at the point (0,5). The thief is at the point where the ordinary is 0. The thief and the policeman are equidistant from the jewel box.

To find,

The position of the thief.

Solution,

The coordinate of the jewel box is at the origin i.e. (0,0).

The distance between the policeman and the jewel box is equal to the distance between the thief and the jewel box.

The distance between the policeman and the jewel box can be found by the distance formula.

Distance between two coordinates = √(x2-x1)2-(y2-y1)2

Distance between(0,0) and (0,5)

√25=5 units.

let the abscissa of thief position is x.

Distance between the thief and the jewel box=5.

The coordinate of the thief position is (x, 0).

Now,

5=√x2

x=5

So, the position of the thief is (5,0).

#SPJ1

Answer 2

Answer:

(0,5) plz mark me as brainlest

Step-by-step explanation:

as it is clear from the question that the thief and police are equidistant from the origin and moreover the ordinate of the position of the thief on the axis is given as zero hence the position is (0,5)

thankyou