Question

a policeman goes after a Thief which is 125 m ahead of him. if the policeman runs 1 km in 8 Minute And The Thief runs a kilometre in 10 minutes how far will the thief have gone before his caught?

Answer 1

Given

Starting Distance between policemen and thief =125m

Speed of policemen =1km in 8 min

Speed of thief =1km in 10min

So policemen speed in one min=1/8 km/min

Changing it in meter/s

1km/min =1000/60 m/s


So 1/8 km /min=1000/60x8

=100/48 m/s

Similarly speed of thief =(1/10) x 1000/60

=1000/600

=10/6 m/s


Now if policemen covers the extra distance difference then thief

D=125


Now policemen and thief are moving in same direction then speed

S=10/6-100/48

S=(100-80)/48

S=48x20

S=96m/s

Time =d/s

Time=125/96

Time=1.30m/s

Distance coverd by thief in this time

=125+10/6 x1. 30

=127. 1667m


The distance covered by thief before caught. =127.1667m