A policeman sees a chain snatcher at a distance of 50 m. He starts chasing the chain snatcher who is running with a speed of 2 m/s while the policeman chasing him with a speed of 4 m/s. Find the distance covered by the chain snatcher when he is caught by the policeman. Your
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The distance covered by the chain snatcher when he is caught by the policeman is 50 m.
Explanation:
The relative speed is equal to difference of speeds.
Let the velocity of chain snatcher is v and policeman is V.
Then relative speed of the policeman is = (V-v)
= 4 m/s - 2 m/s = 2 m/s
The a chain snatcher at a distance of 50 m from policeman.
So, to catch the snatcher the policeman in has to gain 50 m in time,
( as time = distance /speed)
now total distance covered by the policeman in time 25 s is
=
= 100 m.
Therefore distance covered by the snatcher,
= 100 m - 50 m
= 50 m
Thus, the distance covered by the chain snatcher when he is caught by the policeman is 50 m.
#Learn More: speed, distance and time.
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