Question

A policeman sees a chain snatcher at a distance of 50 m. He starts chasing the chain snatcher who is running with a speed of 2 m/s while the policeman chasing him with a speed of 4 m/s. Find the distance covered by the chain snatcher when he is caught by the policeman. Your

Answer 1

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Answer 2

The distance covered by the chain snatcher when he is caught by the policeman is 50 m.

Explanation:

The relative speed is equal to difference of speeds.

Let the velocity of chain snatcher is v and policeman is V.

Then   relative speed of the policeman is = (V-v)

= 4 m/s - 2 m/s = 2 m/s

The a chain snatcher at a distance of 50 m  from policeman.

So, to catch the snatcher the policeman in has to gain 50 m in time,

$t = \frac{50m}{2m/s} = 25 s$                 ( as  time = distance /speed)

now total distance covered by the policeman in time 25 s is

= $25s\times4m/s$

= 100 m.

Therefore distance covered by the snatcher,

= 100 m - 50 m

= 50 m

Thus, the distance covered by the chain snatcher when he is caught by the policeman is 50 m.

#Learn More: speed, distance and time.

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