Question

A policeman starts running after a thief who is 200 ft ahead of him.The policeman runs 8 ft per second and the thief runs 6 ft per second. When and where will the policeman catch the thief?​

Answer 1

Answer:

800ft, 100s

Step-by-step explanation:

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Answer 2

Answer:

800ft , 100s

Step-by-step explanation:

suppose thief run 'x' ft and caught at that position.

so total time taken by thief=x/6 sec for covering 'x' m.

in this time(x/6 s ) police run total distance=(x/6)*8.

so ,    

       (x/6)*8=200 +x   {as thief was initially 200ft away from police}

       x=600 ft.

     so distance covered by policeman from its initial pos= 600ft +200ft= 800ft.

time taken by policeman=800/speed of policeman

                                        =800/8

                                          =100s.