Question

A polygon has 27 diagnals how many sides does it hv

Answer 1

A polygon having n sides has n(n-3)/2 diagonals.

Here we have 27 diagonals so

2*27 = 54 = n^2 - 3n, or

n^2 - 3n - 54 = 0, or

(n-9)(n+6) = 0, so

n = 9 and -6 (which is inadmissible).

So the polygon has 9 sides.

Answer 2

Using the digits 4,6,3,2 form a number which when rounded off to nearest hundreds, give 6400