Math, asked by shubham5575, 11 months ago

a polygon has 27 diagonal. how many sides does it have​

Answers

Answered by Anonymous
0

Answer:

9

Step-by-step explanation:

Formula to calculate the diagonal of a polygon = n(n-3)/2 when n is the side of the polygon.

So,

n(n-3)/2 = 27

or,

n(n-3) = 54

or,

n²-3n-54 = 0

or,

(n-9)(n+6) = 0

or,

n = 9 , -6

or,

n = 9 [∵ Side of Polygon should be in +ve integers.]


Anonymous: It is right
shubham5575: yes but do it with esay method please
Answered by karthik961
1

no of diagonals if a polygon of 'n' is given by n(n-3)/2

given it has 27 diagonals..

n(n-3)/2 = 27

n(n-3)=54

n^2-3n-54=0

n^2-9n+6n-54=0

n[n-9]+6[n-9]=0

[n-9][n+6]=0

n=9,-6...but side can't be negative..

hence n=9..i.e, it is has 9 sides..


shubham5575: wrong
karthik961: corrected bro..
shubham5575: ans is 9
shubham5575: bro please write your ans in comment box but ans should be 9 please its urgent i have to see this in tution
karthik961: i edited bro..
karthik961: it has 9 sides..
shubham5575: wait be online
shubham5575: bro how 0 form
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