A polygon has 27 diagonal . how many sides does it have?
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Answered by
7
Answer:
No. Of diagonals = n(n-3)/2 = 27
n(n-3) = 54
n^2 - 3n -54 = 0
n^2 - 9n + 6n - 54 = 0
n(n-9) + 6(n-9) = 0
(n-9)(n+6) = 0
n = 9, -6
(excluding -6)
n = 9
The polygon has 9 sides.
Answered by
0
The shape have 9 sides.
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