Math, asked by sportabc3, 1 year ago

A polygon has 27 diagonals, how many sides does it have

Answers

Answered by Ashk432

Answer: 9

Step-by-step explanation:

No. Of diagonals = n(n-3)/2 = 27

n(n-3) = 54

n^2 - 3n -54 = 0

n^2 - 9n + 6n - 54 = 0

n(n-9) + 6(n-9) = 0

(n-9)(n+6) = 0

n = 9, -6

(excluding -6)

n = 9

sportabc3: Ashk432 , its okay but could you please expalin me how you get n(n-9) + 6(n-9) = 0

(n-9)(n+6) = 0

n = 9, -6

sportabc3: (n-9) (n+6) =0 how

Ashk432: Middle term splittung

Ashk432: Splitting*

Ashk432: Hmm

sportabc3: Please explain for me how it is coming ( n-9) (n+6) , If splitting then why we are taking only one (n-9)

Ashk432: It cant be -ve bcs no. Of sides are always positive

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