A polygon has 44 diagonals, find no of sides.
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The number of diagonals for an n sided polygon = [n(n-3)]/2
therefore, 44 = [n(n-3)]/2
=> n*n - 3n - 88 = 0
=> n = 11
So, the no. of sides = 11
therefore, 44 = [n(n-3)]/2
=> n*n - 3n - 88 = 0
=> n = 11
So, the no. of sides = 11
bpss1:
no question like this in AP
yes it's advanced ques.
from ehich book?
which book?
Rd Sharma ?
i study from spectrum
why did u report my answer bpss1
i wanted to mark it as branliest
i didnt know how to
it's okk
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