a polygon has 44 diagonals.find the no. of sied of polygon..?
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Answer:
11 sides
Step-by-step explanation:
Number of diagonals = n(n - 3) / 2 where n is the number of sides.
Since we are given that there are 44 diagonals:
n(n - 3) / 2 = 44
Solve n:
n(n - 3) / 2 = 44
n (n - 3) = 88
n² - 3n = 88
n² - 3n - 88 = 0
(n - 11)(n + 8) = 0
n = 11 or n = -8 (rejected, since number of sides cannot be negative)
Answer: There are 11 sides
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