a polygon has 44 diagonals. the number of its sides is
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I think 22 is the answer
faridalam1:
no that's wrong
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Diagonals in a polygon= n(n-3)/2
44=n(n-3)/2
44*2=n(n-3)
88=n^2-3n
n^2-3n-88=0
n^2-11n+8n-88=0
n(n-11)+8(n-11)=0
(n-11)(n+8)=0
n-11=0 n+8=0
n=11 n=-8.
Since sides in any polygon can't be negative.So possible value is 11.
44=n(n-3)/2
44*2=n(n-3)
88=n^2-3n
n^2-3n-88=0
n^2-11n+8n-88=0
n(n-11)+8(n-11)=0
(n-11)(n+8)=0
n-11=0 n+8=0
n=11 n=-8.
Since sides in any polygon can't be negative.So possible value is 11.
lajawab
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