A polygon has a 54 diagonals find number of sides of the polygon is
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n×(n-3)/2=54
n×(n-3)=54×2
n×(n-3)=108
n^2-3n-108=0
n^2+9n-12n-108=0
n(n+9)-12(n+9)=0
(n+9)×(n-12)=0
we take
n-12=0
n=12
so no.of side =12
n×(n-3)=54×2
n×(n-3)=108
n^2-3n-108=0
n^2+9n-12n-108=0
n(n+9)-12(n+9)=0
(n+9)×(n-12)=0
we take
n-12=0
n=12
so no.of side =12
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