Math, asked by selvakumar14389, 5 months ago

a polygon has five diaganols then the number of sides in the polygins. a)5. b)3 c)6 d) 4​

Answers

Answered by Anonymous
4

Step-by-step explanation:

option b 3

Answered by ojaswa67
17

Answer:

↣5

Step-by-step explanation:

We know that,

↣Number of diagonals of a polygon=

 \frac{n(n - 3)}{2}

↣According to the question,

↣ \frac{n(n - 3)}{2}  = 5 \\ ↣n(n - 3) = 10 \\ ↣ {n}^{2}   - 3n = 10 \\ ↣ {n}^{2}  - 3n - 10 = 0 \\ ↣ {n}^{2}   +  2n  -  5n - 10 \\ ↣n(n + 2) - 5(n + 2) \\↣( n - 5)(n + 2)

↣n - 5 = 0 \\↣ n = 5

OR,

↣n + 2 = 0 \\↣ n =  - 2 \\

Neglected, because the side of polygon can't be negative.

Hence,

n = 5

The side of polygon are 5.

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