A polygon has vertices J(2,3), K(4,3), L(4,7) , and M(2,7) . What is the area of the polygon?
Answers
Given coordinates are
Coordinates of J be (2, 3)
Coordinates of K (4, 3)
Coordinates of L (4, 7)
Coordinates of M (2, 7).
[ Please see the attachment ].
From graph we concluded that
JK = 2 units
KL = 4 units
LM = 2 units
MJ = 4 units
Also,
JK is perpendicular to KL.
KL is perpendicular to LM
LM is perpendicular to MJ
MJ is perpendicular to JK
It implies, JK = LM = 2units and KL = MJ = 4 units.
As we know that,
In a quadrilateral, if all the opposite pair of sides are equal and angle between the sides is 90°, then quadrilateral is a rectangle..
So, this figure, JKLM is a Rectangle.
Now, Area of rectangle JKLM= JK×KL = 4 × 2 = 8 sq. units.
Additional Information :-
Let's solve the same type of problem!!
Question :- A polygon has vertices A ( 2, 3), B (2, 1), C(0, 1) and D (0,3). Find the Perimeter of the polygon.
Solution:-
Given coordinates are
Coordinates of A be (2, 3)
Coordinates of B (2, 1)
Coordinates of C (0, 1)
Coordinates of D (0, 3).
[ Please see the attachment ].
From graph we concluded that
AB = 2 units
BC = 2 units
CD = 2 units
DA = 2 units
Also,
AB is perpendicular to BC.
BC is perpendicular to CD
CD is perpendicular to DA
DA is perpendicular to AB.
It implies, AB = BC = CD = DA = 2 units.
As we know that,
In a quadrilateral, if all the 4 sides are equal and angle between the sides is 90°, then quadrilateral is a square.
So, this figure, ABCD is a square.
Now, Perimeter of a square = 4 × side = 4 × 2 = 8 units.
Answer:
Step-by-step explanation:
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