a polygon have 27 diagonals. how many sides does it have?
the formula is n(n-3)/2
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Answer:
The polygon has 9 sides. It is a Nonagon.
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n(n-3)/2=27
n(n-3)=27×2
n(n-3)=54
n²-3n=54
n²-(9-6)n-54=0
n²-9n+6n-54=0
n(n-9)+6(n-9)=0
n+6=0 n=0-6 n=-6
n-9=0 n=0+9 n=9
As the sides cannot be negative the number of sides will be 9
it is a nonagon....
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