Math, asked by Adinarayana9773, 7 months ago

A polygon having 27 diagonals , how many sides does it have?

Answers

Answered by priyanshu4571
1

Answer:

Hey mate here is the answer

Answer is 9 sides.

Hope it helps you

Please mark me as brilliant

Answered by battuadityarao
2

Answer:

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Step-by-step explanation:

→  The formula for the no. of diagonals of a ’n' sided polygon is n(n-3)/2 .

It works for triangle (0 diagonals) , quadrilateral (2 diagonals) , pentagon (5 diagonals) and for every another polygon.

Let's come to the problem.

No. Of diagonals = n(n-3)/2 = 27

n(n-3) = 54

n^2 - 3n -54 = 0

n^2 - 9n + 6n - 54 = 0

n(n-9) + 6(n-9) = 0

(n-9)(n+6) = 0

n = 9, -6

(excluding -6)

n = 9

The polygon has 9 sides.

It is a Nonagon.

Hurry! We found it.

The formula I mentioned can be derived.

No. of sides = No. of vertices = n

Each diagonal joins two of the vertices.

The no. of ways (n) vertices can be joined (two at a time) is nC2.

But we are also including (n) sides by joining two vertices at a time.

To get only the no. of diagonals, we must subtract the (n) sides from nC2.

Hence,

No. of diagonals = nC2 - n = (n(n-1)/2!) - n

= (n(n-1) - 2n)/2 = n(n-3)/2

                                             (OR)

→   We know that, to find diagonals of a polygon, we use the formula n(n-3)/2 where n is the number of sides. It is given that the polygon have 27 diagonals.

So,

=>n(n-3)/2=27

=>n²-3n=27×2

=>n²-3n=54

=>n²-3n-54=0

=>n²-(9–6)n-54=0

=>n²-9n+6n-54=0

=>n(n-9)+6(n-9)=0

(n+6)=0; (n-9)=0

n=-6; n=9

n should not be negative so 9 is the number of sides.

So the polygon have 9 sides which is also called a nanogon.

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