Question

A polygon is shown:

A polygon MNOPQR is shown. The top vertex on the left is labeled M, and rest of the vertices are labeled clockwise starting from the top left vertex labeled, M. The side MN is parallel to side QR. The side MR is parallel to side PQ. The side MN is labeled as 3 units. The side QR is labeled as 7 units. The side MR is labeled as 3 units, and the side NO is labeled as 2 units.

The area of polygon MNOPQR = Area of a rectangle that is 9 square units + Area of a rectangle that is ___ square units. (Input whole numbers only, such as 8.)

Answer 1

Step-by-step explanation :

[ Check the attachment for the polygon MNOPQR ]

We have drawn another point S.

Step 1. Finding the area of the square MNSR

• Here, one side of the square = 3 units
• Then its area = 3 × 3 sq. units = 9 sq. units

Step 2. Finding the area of the rectangle OPQS

• Here, length = (7 - 3) units = 4 units and width = (3 - 2) units = 1 unit
• Then its area = 4 × 1 sq. units = 4 sq. units

Step 3. Finding the area of the polygon MNOPQR

• Therefore the area of the polygon MNOPQR = the area of the square that is 9 sq. units + the area of the rectangle that is 4 sq. units.

Answer:

The area of polygon MNOPQR = Area of a rectangle that is 9 square units + Area of a rectangle that is 4 square units.

Answer 2

Answer:

i don't know sorry

Step-by-step explanation:

i don't know sorry

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