Question

A polygon of 10 side has .......... diagonals. 1. 35 2. 45 3. 72 4. 90. ​

Answer 1

Step-by-step explanation:

Assume that there are 10 points in a plane where no 3 of them are collinear which are the verticews of the given polygon, <br> The number of different lines that can be formed by joining these 10 points is `.^(10)C_(2)`. <br> We know in any polygon the lines joining non-adjacent vertices are called diagonals. <br> Hence, the required number of diagonals=Number of lines formed -Number of sides of the polygon `=.^(10)C_(2)-10=35`. <br> Using the formula, the number of diagonals in the above problem `=(10(10-3))/(2)=35

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Answer 2

Answer:

35 is the answer

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