Question

A polygon of '9' sides each of length '2'
is inscribed in a circle, the radius of the
circle is​

Answer 1

Answer:

Let AB=2 unit be one of the sides of the polygon.

Then, ∠AOB=

9

2π

where O is the centre of the circle.

If OL⊥AB, then AL=1 and ∠AOL=

9

π

∴ Radius of the circle=OA=ALcsc

9

π

=csc

9

π

Step-by-step explanation:

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Answer 2

Perimeter of polygon=9×2=18

Perimeter of polygon=circumference/perimeter of circle

18=

$2\pi \: r$

18=2×22/7×r

18×7/22=r

63/11=r